TCS – Questions -12
1.
Raja
and Rakesh started a business and invested Rs 20,000 and Rs 25,000
respectively. After 4 months Rakesh left and Mukesh joined by investing Rs
15,000. At the end of the year there was a profit of Rs 4600. what is the share
of profit of Mukesh?
Answer: Rs 1,200
Raja’s
investment of Rs 20,000 was in the business for 12 months. Total amount Rs
2,40,000
Rakesh’s investment of Rs 25,000 was there
for 4 months. Total amount
Rs 1,00,000
Mukesh’s investment of Rs 15,000 was there
for 8 months. Total amount
Rs 1,20,000
Thus total turnover of business is Rs
4,60,000. On this turnover the profit earned is Rs 4,600
Mukesh
share of profit is 4,600 * 1,20,000/4,60,000 = Rs 1,200
2.
16
men can complete a work in 24 days , while 48 children can do it in 16 days. 12
men started the work , after 14 days 12 children joined the work. In how many
days will all of them do the remaining work ?
Answer: 12 days
16
Men can complete the work in 24 days. 16 Men in one day can do 1/24 work.
1
man in one day can do 1/24*16 = 1/384 work.
48
children can do the work in 16 days. 48 Children in one day can do 1/48 work.
1
child in one day can do 1/48*16 = 1/768 work.
Now,
12 men work for 14 days. The completed work is 12*14/384 = 168/384 work.
The
remaining work is 1 – 168/384 = 216/384.
Now,
12 men and 12 children in one day can do 12/384 + 12/768 = 36/768 work.
The
remaining work is 216/384 and the 12 men and 12 children will take
(216/384)
/ (36/768) days. Reducing this you will
get a value 12 days.
3.
How
many motor vehicle registration number plates can be formed with the digits
1,2,3,4,5(no digits being repeated ) if given that registration number can have
1 to 5 digits?
Answer: 35
Number plates with one digit =5c1ways
= 5
Number plates with two digits =5c2ways = 10
Number plates with three digits =5c3 ways = 10
Number plates with four digits =5c4 ways = 5
Number plates with five digits =5c5 ways = 5
Total=35ways
Number plates with two digits =5c2ways = 10
Number plates with three digits =5c3 ways = 10
Number plates with four digits =5c4 ways = 5
Number plates with five digits =5c5 ways = 5
Total=35ways
4.
5000
voted in an election between two candidates. 14% of the votes were invalid. The
winner won by a margin approximately closer to 15%. Find the number of votes
secured by the winner.
a)2650 b)2564 c)2473 d)2360
Answer:
C.a)2650 b)2564 c)2473 d)2360
Total votes polled 5000. 14% was invalid.
Hence valid votes were 5000 – 700 = 4300
The winner secured a margin of 15% over the
rival. Thus the winner’s votes were
4300*15/100 = 645 votes more than the
rival. Excluding this the remaining votes were equally shared by both the
candidates. Each candidate got (4300 – 645) / 2 = 1827.5.
Adding the winner’s margin of 645 votes to
this figure, we get the total number of votes secured by the winner approximately as 1827.5 + 645 = 2473.
5.
In
2003 there are 28 days in February and 365 days in the year. In 2004 there are
29 days in February and 366 days in the year. If the date March 11 2003 is
Tuesday, then which one of the following would be the day for date March 11
2004?
a)
Monday b)
Wednesday c)
Thursday d) Friday
Answer: C.
Simple.
If the year 2004 was not a leap year then the date March 11, would be a day
ahead, ie Wednesday. Since 2004 is a leap year and March comes after February
that has one extra day the date March
11, 2004 would be Thursday.
6.
A
child was looking for his father. He went 90 mts in the east before turning to
his right. He went 20 mts before turning to his right again to look for his
father to his uncle’s place 30 mts from this point. His father was not there. From
here on he went 100 mts to the north before meeting his father in the street. How
far away from the starting point did the son meet his father?
Answer: 100 meters.
The
route the boy takes would appear as under. We have to find the distance from
the starting point to end point.
Distance
between A and B 90 mtrs. B and C 20 meters .
Distance between C and D 30 meters.
Distance between D and F 100 meters.
From this information we now arrive at the following: Distance between A and E = 90 – 30 = 60
mtrs.
Likewise
distance between E and F = 100 – 20 = 80 mtrs.
Now applying the Pythagoras theorem we arrive the distance of A and F as
100 meters.
7.
How
many positive integers less than 500 can be formed using the numbers 1,2,3,and
5 for digits, each digit being used only once.
Answer: 74
Only four
numbers are available and repetition is not allowed.
Number of
single digit numbers 4C1 = 4
Number of
double digit numbers 4C2 = 6 * 9 54
Number of three
digit numbers 4C3 =
4 * 4
16
Total number of positive digits 74
8.
A
circular swimming pool is surrounded by a concrete wall 4 feet wide.if the area
of the wall is 11/25 of the area of the pool, then the radius of the pool in
feet is?
Answer: 20 feet.
Let
the radius of the pool be ‘r’. The thickness
of the wall is 4 ft.
Area
of the pool +area of the wall = pi(r+4)2
Area
of the pool = pi*r2.
Area
of the wall alone = pi(r+4)2
– pi*r2 = 11/25 (pi*r2)
Solving
this we get the value of ‘r’ as 20 ft.
9.
A
survey of n people in the town of Badaville found that 50% of them prefer brand
A.
Another
survey of 100 people in the town Chottaville found that 60% prefer brand A. In
total 55% of all the people surveyed together prefer Brand A. What is the total
number of people surveyed?
Answer: 200 persons (a very simple
question)
Assume
the number of people surveyed Badaville as 100. Then those preferring Brand A
is 50
In
Chotaville those preferring brand A is 60% of 100 surveyed. ie 60.
Total
preference for brand A in both the places is 110 which is 55% of the number
surveyed. Hence, the total number of
people surveyed is 200.
10.
One
day Eesha started 30 min late from home and reached her office 50 min late
while driving 25% slower than her usual speed. How much time in min does Eesha
usually take to reach her office from home?
Answer: 60 minutes
Let
the distance be D and the usual speed S. Then the time taken to travel is D/S=T (1)
The
new speed is (S- 1/4S) = ¾ S. The new time taken is D/3/4 S = T + 20 (50 – 30) (2)
Equating
(1) and (2) we get the value of T as 60
minutes.
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