Quans - 14 (Bank Exams)

Quans – 14 (Bank Exams)

1. R = QS—4 where S=8 and R=16. When S=10 then R is equal to:

(a) 11                     (b) 14                    (c) 20                     (d) 21
Answer: (d)

R = QS – 4. Substituting the values of R and S we get -> 16 = 8Q – 4 -> 8Q = 20 -> Q = 2.5

Hence when S = 10 the equation will become -> R = (10*2.5) – 4 = 21.

2. The average of five positive numbers is 213. The average of the first two numbers is 233·5 and the average of last two numbers is 271. What is the third number?

(a) 64                     (b) 56                    (c) 106                   (d) None of these
Ans : (b)

The total of five numbers -> 213 x 5 = 1065 less

The total of first two numbers -> 233.5 x 2 = 467 ie 1065 – 467 = 598 less

The total of last two numbers ->  271 x 2 = 542  ie  598 – 542 = 56

The third number is 56.

3. The number of employees in Companies A, B and C are in the ratio of 4 : 5 : 6 respectively. If the number of employees in the three Companies  increases by 25%, 30% and 50% respectively, then what will be the new ratio of employees working in Companies A, B and C respectively ?

(a) 13 : 10 : 18     (b) 10 : 13 : 17    (c) 13 : 15 : 18     (d) None of these
Ans : (d)
The total parts of employees in the three companies initially is 4 + 5 + 6 = 15.

So for convenient sake let us assume the total employees in the three companies as 450.

Then the number of employees in A, B and C will be …. 120, 150 and 180.

The percentage increase in the three companies takes place as 25%, 30% and 50%.

The number of employees after increase in company A will be 120 + 25% -> 120 + 30 = 150

The number of employees after increase in company B will be 150 + 30% -> 150 + 45 = 195

The number of employees after increase in company C will be 180 + 50% -> 180 + 90 = 270

Hence the new ratio of employees is 150 : 195 : 270 reducing -> 10 : 13 : 18 (Not there in the choice)

  

4. 7414 + 3698 + 1257 + 1869 = ?

(a) 14328              (b) 14438             (c) 13428              (d) 13248             (e) None of these
Ans : (e)

5. (2640 ÷ 48) × (2240 ÷ 35) = ?

(a) 3520                (b) 3515                (c) 3495                (d) 3490                (e) None of these
Ans : (a)

6. The divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46 then the dividend is how much?

(a) 4236                (b) 4306                (c) 4336                (d) 5336                (e) None of these
Ans: (d)

Dividend = Divisor x Quotient + Reminder.

The reminder is 46 and hence the divisor = 46 x 5 = 230.

The divisor is 10 times the quotient. Thus we have the quotient as 230/10 = 23.

We now have the equation Dividend = 230 x 23 + 46 = 5336.

Hence the answer is 5336.

7. The digit in unit’s place of product 81*82……..*89 is:

(a) 0                       (b) 2                       (c) 6                       (d) 8                       (e) None of these

Ans: (a)

Please note the number of ‘0’s in any factorial is given by the formula x/5 + x/5² where ‘x’ is the number of terms in the factorial and the quotient alone is taken for the number of zeros leaving the reminder.

Applying the above we have 9/5 + 9/25 this will give only one completed quotient and hence the answer is one ‘0’

8. If -1 ≤ x ≤ 2 and 1≤ y ≤ 3 then least value of 2y-3x is :

(a) 0                       (b) -3                     (c) -4                      (d) -5                     (e) None of these

Ans: (a)

Since ‘x’and ‘y’ are of positive value we shall work out the two possibilities.

Let ‘x’ be 1 and ‘y’ be 2. Then we have the value 2*2 – 3*1 =1 (not there in the choice)

Let ‘x’ be 2 and ‘y’ be 3. Then we have the value 2*3 – 3*2 = 0 (available in the choice)

9. If n is a negative (–ve) no. then which of the following is least.

(a) 0                       (b) –n                    (c) 2n                     (d) n^2                 (e) None of these
Ans: (c)

10. On selling a certain commodity for Rs. 425, there is as much gain as loss on selling it for Rs. 355. The C.P. of the commodity is

(a) Rs. 370           (b) Rs. 385           (c) Rs. 390            (d) Rs. 400          

Ans: (c)
Let ‘x’ be the profit and loss in the two transactions. Then we have

C.P + x = 425 ……….(i)

C.P – x = 355 ……….(ii)    subtracting (ii) from (i) we get 2x = 70 and ‘x’ =35.

From (ii) C.P = 355 + x -> 355 + 35 = 390.

11. A person bought some oranges @ Rs. 10 per dozen and bought the same number of oranges @ Rs. 8 per dozen. He sold these oranges @ Rs. 11 per dozen and gained Rs. 120. The total number of oranges bought by him was:

(a) 30 dozen       (b) 40 dozen       (c) 50 dozen       (d) 60 dozen
Ans: (d)

The average cost of the two purchases of Oranges is (10 + 8)/2 = Rs 9 per dozen.

The oranges were sold for Rs 11 per dozen giving a profit of Rs 2/- per dozen.

The total profit was  Rs 120 and the number of oranges originally purchased by him

Was 120/2 = 60 dozens.

12. A no. when divided by 114 leaves the remainder 21. If the same no. is divided by 19 the remainder will be:

(a) 1                       (b) 2                       (c) 7                       (d) 21                    (e) None of these
Ans: (b)

Since 19 is divisor of 114 without any remainder, divide the remainder 21 by 19 that will leave a remainder of 2

13. Which largest No. of 5 digits is divisible by 99:

(a) 99909              (b) 99981             (c) 99990              (d) 99999             (e) None of these
Ans: (c)