PLACEMENTS: July 2015

Sunday, 26 July 2015

Accenture - Verbal & Reasoning - 8

Accenture – Verbal & Reasoning - 8

1. Read the information given below and answer the questions that follow.

Six friends are sitting in a circle and are facing the centre of the circle. Deepa is between Prakash and Pankaj. Priti is between Mukesh and Lalit. Prakash and Mukesh are opposite to each other.

I. Who are the neighbours of Mukesh?

A. Prakash and Deepa B. Deepa and Priti

C. Priti and Pankaj D. Lalit and Priti

Ans: (C)

II. Who is sitting opposite to Priti ?

A. Prakash B. Deepa

C. Pankaj D. Lalit

Ans: (B)

III. Who is just right to Pankaj?

A. Deepa B. Lalit

C. Prakash D. Priti

Ans: (A)

2. The questions below is based on the information given

1. A + B means A is the mother of B.

2. A - B means A is the sister of B.

3. A * B means A is the father of B.

4. A β B means A is the brother of B.

I. Which of the following means that N is the maternal uncle of M?

A. N β P - L + E - M B. N - Y + A β M

C. M - Y * P - N D. N β C + F * M

Ans: (A)

II. Which of the following means Q is the grandfather of P?

A. P + N * M * Q B. Q * N * M + P

C. Q β M β N * P D. None of these

Ans: (D)

3. Some of the letters are missing in the series and these are given as alternatives below. Please choose the correct group of letters that would fit in the blank places to complete the series.

gfe _ ig _ eii _ fei _ gf_ ii

(A) eifgi

(B) figie

(D) ifige

Ans: (C)

4. Some of the letters are missing in the series and these are given as alternatives below. Please choose the correct group of letters that would fit in the blank places to complete the series.

ab _ aa _ bbb _ aaa _ bbba

(A) abba

(B) baab

(D) abab

Ans: (B)

5. Various terms of an alphabet series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives.

Z, S, W, O, T, K, Q, G, ?, ?

(A) N, C

(B) N, D

(D) O, D

Ans: (A)

6. Choose the correct alternative that will continue the same pattern and replace the question mark

5824, 5242, ?, 4247, 3823

(A) 4467

(B) 4718

(D) 5164

Ans: (B)

7. First bunch of bananas has (1/4) again as many bananas as a second bunch. If the second bunch has 3 bananas less than the first bunch, then the number of bananas in the first bunch is?

Ans: (15)

Let A and B be the number of bananas in bunch 1 and 2 respctively.

We now have an equation: A = 5B/4 and B = A – 3.

Substituting the value of B in the first equation and solving we get A = 15.

8. Mr. X, a mathematician, defines a number as 'connected with 6 if it is divisible by 6 or if the sum of its digits is 6, or if 6 is one of the digits of the number. Other numbers are all 'not connected with 6'. As per this definition, the number of integers from 1 to 60 (both inclusive) which are not connected with 6 is

(A) 18

(B) 22

(D) 43

Ans: (D)

The numbers eliminated according to the question are:

6, 12, 15, 16, 18, 24, 26, 30, 33, 36, 42, 46, 48, 51, 54, 56, 60 (Totally 17 numbers)

9. Between two book-ends in your study are displayed your five favourite puzzle books. If you decide to arrange the five books in every possible combination and moved just one book every minute, how long would it take you?

(A) 1 hour

(B) 2 hours

(D) 4 hours

Ans: (B)

The books can be arranged in 5! Ways -> 120 ways. Since each arrangement take one minute the total time to arrange in all the ways will be 120 minutes or 2 hours.

10. Six products U,V,W,X,Y and Z are to be placed in display windows of a shop. There are six display windows numbers 1,2,3,4,5,6 and one product is to be put in one window. Moreover U cannot be immediately to the left or immediately to the right of V. W must be immediately to the left of X, Z cannot be in window number 6.

If X is placed in window no:3, then U must be placed in which window?

Ans: Window No 6

The arrangement will be as follows: Z W X V Y U

11. Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the meantime, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point?

Ans: 65 km (Draw a figure and you will get the answer)

Similar question was there in a CAT paper more than a decade ago.

12. A boy rode his bicycle northward, then turned left and rode 1 km and again turned left and rode 2 km. He found himself 1 km west of his starting point. How far did he ride northward initially?

(A) 1 km

(B) 2 km

(D) 5 km

Ans: (B) Simple question. Draw a figure to get the answer.

13. Read the paragraph carefully and answer the question given below it.

The future of women in India is quite bright and let us hope that they will justify their abilities by rising to the occasion. Napoleon was right when he declared that by educating the women we can educate the whole nation. Because a country can never rise without the contribution of 50% of their population.

The passage best supports the statement that:

(A) India is striving hard for the emancipation of women.

(B) all women should be well educated.

(D) Women ought to be imparted full freedom to prove their worth and contribute to the progress of the nation.

Ans: (D)

14. Read the paragraph carefully and answer the question given below it.

The virtue of art does not allow the work to be interfered with or immediately ruled by anything other than itself. It insists that it alone shall touch the work in order to bring it into being. Art requires that nothing shall attain the work except through art itself.

This passage best supports the statement that:

(A) art is governed by external rules and conditions.

(B) art is for the sake of art and life.

(D) artist realises his dreams through his artistic creation.

Ans: (C)

15. The taxi charges in a city comprise of a fixed charge, together with the charge of the distance covered. For a journey of 16 km, the charges paid are Rs. 156 and for a journey of 24 km, the charges paid are Rs. 204. What will a person have to pay for travelling a distance of 30 km?

Ans: Rs 240

Let ‘x’ be the fixed charge and ‘y’ the per km charge. Then we have two equations as under:

X + 16y = 156 ----------------- (i)

X + 24y = 204 ---------------- (ii)

Subtracting (i) from (ii) we get the value of Y as Rs 6.00 and the value of x as Rs 60.00

Substituting these values, the amount for a distance of 30 km will be:

60 + (30*6) = 240.00

Thursday, 16 July 2015

TCS - 2015 - 2

TCS – 2015 - 2

1. Rajiv can do a piece of work in 10 days , Venky in 12 days and Ravi in 15 days. They all start the work together, but Rajiv leaves after 2 days and Venky leaves 3 days before the work is completed. In how many days approximately the work is completed?
(a) 5
(b) 6
(c) 9
(d) 7
Ans: (d)

Rajiv in one day does 1/10 work.

Venky in one day does 1/12 work

Ravi in one day does 1/15 work. All the three in one day does – 1/10 + 1/12 + 1/15 = ¼ work.

They work for 2 days and the work completed is ¼ * 2 = ½. Remaining work is ½

Venky and Ravi in one day do – 1/12 + 1/15 = 3/20 work.

Hence to complete the remaining ½ work they would have taken -> ½ * 20/3 = 10/3 or 3 1/3 days. Venky after doing work for 1/3 day leaves.

Thus in 1/3 days the work done by both is 3/20 * 1/3 = 1/20 work.

Remaining work is ½ - 1/20 -> 9/20

To complete this Ravi will take -> (9/20) / (1/15) -> 9/20 * 15 -> 6 ¾ days -> roughly 7 days.

2. On a 26 question test, five points were deducted for each wrong answer and eight points were added for each correct answer. If all the questions were answered, how many were correct, if the score was zero?
(a) 10
(b) 12
(c) 11
(d) 13
Ans: (a)

Let the number of correctly answered questions be ‘x’. Then we have an equation:

8x – 5(26 – x) = 0.

Solving, we get the value of ‘x’ as 10.

3. X = 101102103104105106107......146147148149150 (From numbers 101-150). Find out the remainder when this number is divided by 9.

Ans: 2

The rule of divisibility for 9 is the sum of the digits is to be divisible by 9.

To arrive at the sum of the digits we calculate the sum in the unit, tenth and the hundredth places separately.

(a) Sum of the digits in the hundredth place is – 1 * 50 = 50

(b) Sum of the digits in the tenths place is:

1*10 + 2*10 + 3*10 + 4*10 + 5*1 = 105. (Note the initial 0*9 will give only ‘0’ value)

Totalling (a), (b) and (c) we get …380. This when divided by 9 will leave a reminder 2.

4. A number is 101102103104...150. As in the earlier question what is the reminder if

divided by 3?

Ans: 2

The rule of divisibility for 3 is the same as that of 9 the reminder will remain the same as 2

5. 7^1+7^2+7^3+.......+7^205.

In the above series how many numbers have 3 in the unit place?

Ans: 51

The unit digits for 7^1, 7^2, 7^3 and 7^4 are 7, 9, 3 and 1. These digits repeat again and again. In other words, the unit digits in 7 to the power repeat after every fourth power and each can be called one cycle.

Thus in 7^205 we have 205/4 -> 51 completed cycles.

Thus 51 powers of 7 will have unit digit as 3.

Hence the answer is 51.

6. In paper A, one student got 18 out of 70 and in paper B he got 14 out of 30. In which paper he did fare well?

Ans: Paper B

A simple question to answer.

Percentage of marks scored in Paper A is 18/70*100 = 25.7%

Percentage of marks scored in Paper B is 14/30*100 = 46.6%

In paper B he fared well.

7. Find the total no of divisors of 1728 (including 1 and 1728)

Ans: 28.

The number of factors of a given number N is given by a^p*b^q*c^r ….

Where a, b, c,…. Are prime numbers and (p+1)*(q+1)+(r+1)*……. are factors.

Applying the above we have 1728 = 2^6*3^3

Hence the factors are (6+1) * (3+1) = 28

8. The sum of two numbers is 45. Sum of their quotient and reciprocal is 2.05. Find the product of the numbers.

Ans: 500

Let x and y be the numbers.

We are given that x + y = 45 (i) and (x/y) + (y/x) = 2.05 (ii)

From (ii) we have (x² + y²) / xy = 2.05. expanding

[(x+y)² – 2xy] / xy = 2.05 -> (x+y)² = 2.05xy + 2xy = 4.05xy

(x+y) = 45. We now have -> 45*45/ 4.05 = xy

Thus xy = 500.

9. A number when divided by 406 leaves remainder 115. What will be the reminder if the number is divided by 29?

Ans: 28

Let the number be N and the quotient X.

Then N = 406X + 115. Since 406 is exactly divisible by 29, to arrive at the answer

We have to divide the reminder 115 alone by 29.

Thus 115/29 reminder is 28.

10. The number of multiples of 10 which are less than 1000, which can be written as a sum of four consecutive integers is
(a) 50
(b)100
(c) 150
(d) 216

Ans: (a)

We can write 10 as (1 + 2 + 3 + 4) four consecutive numbers.

Now adding 5 to each of these digits we get:

6 + 7 + 8 + 9 = 30 (again consecutive four digits.)

Again adding 5 to each of the above digits we get:

11 + 12 + 13 + 14 = 50

From the above we observe that 10, 30, 50, 70 ……that are multiple of 10 have consecutive four digits.

Thus we have 50 numbers that can be written in four consecutive digits between 1 and 1000.

Please note that 20, 40, 60 …… all cannot be written through four consecutive numbers.

Sunday, 5 July 2015

English Verbal - 15 (for Bank Exams)

English – Verbal – 15 (for Bank Exams)

Directions—(Q. 1–15) Read the following passage carefully and answer the questions that follow:

The great sage once had a group of disciples. They were all very bright and eager students and the sage had all the reasons to be proud of them. One day the sage realized that he had imparted enough knowledge to his disciples. Now they were all very learned. There was only one thing the sage had not taught them, and that was the special verse that could bring the dead back to life. The sage knew that such knowledge was too wonderful and could prove to be a dangerous thing in the hands of someone who was not very wise. The sage pondered over this for a long time. But he also knew that if he did not pass on this secret verse, it could die with him. So, at last he called his cleverest disciple aside and said “I am going to teach you a very special verse. If you chant this you can bring to life a dead person or animal. Use only when you need it to and never misuse or test your powers vainly.”

He then called all the disciples together and said, “I am sending you all into the forest for forty days. Go together and come back together. Each one of you has to guide one another and do good things.” So the disciples started out together into the forest. They were all united. But the clever disciple who knew the verse wanted to show he was better than the others. As they walked into the forest, they came across a dead tiger on the way. It was huge and looked wickedly fierce even when dead. The clever disciple stopped and said to the others. “Now I am going to show you what our teacher has taught me alone. He has taught me how to bring life back into the dead.” The others would not believe him and he said, “I would prove it to you by bringing this tiger back to life. “But other disciple said “do not do anything to prove your knowledge vainly. Moreover, if you put life into this tiger, it will only turn on us and kill us all. This will not be a wise thing to do.” But the clever disciple had decided to prove himself and prepared to recite the verse. But before he did so, the other disciples scrambled up to the topmost branches of a big tree nearby. The disciple then recited the magical verse. The tiger slowly began to breathe. “Its working” cried the disciple in excitement and joy. The tiger opened its eyes and saw him jumping and shouting in front of him. Roaring loudly, the tiger pounced on the poor disciple and killed him. The other disciples on the tree watched helplessly as the tiger threw down the dead body of the disciple and went away into the forest. After some time the disciples came down, took the body and went to the sage. The sage looked at them and said, “Now you see what can happen if you don’t use your learning wisely. Let this be a lesson for you.” With that, the sage uttered the magic verse and brought the dead disciple back to life. The sage then taught the verse to all his disciples and sent them into the world to do good. He was sure that after such a lesson, they would be wiser and use their knowledge and learning only for doing good.

1. Why did the other disciples climb the highest branches of the nearby tree?
(a) To save their lives from the tiger
(b) They disliked the clever disciple and were hiding away from him
(c) To enjoy watching the tiger kill the disciple from a safe distance
(d) Because the sage had not taught the other disciples the secret verse
(e) None of these
Ans: (a)

2. Why did the sage send his disciples to the forest?
(a) He wanted to get rid of them.
(b) He had imparted all the knowledge he had and was left with nothing to teach
(c) He wanted them to be killed by a tiger so that he could test his secret verse
(d) So that the disciples could practice his secret verse on the wild animals
(e) None of these
Ans: (e)

3. Which of the following morals can be drawn from the above passage?
(a) A teacher must pass on all his knowledge to others before he dies
(b) Advice of true friends should always be taken
(c) Teachers should always be impartial and should impart knowledge to all uniformly
(d) The knowledge and learning gained should never the misused
(e) None of these

Ans: (d)

4. Why did the sage decide to pass on his secret verse to his disciples?
(a) So that the cleverest of the disciples may teach other disciples as well.
(b) He did not want the verse to die with him
(c) So that the tiger may eat the cleverest disciple
(d) So that he could prove his genius to his disciples
(e) None of these

Ans: (b)

5. What did the sage say to his disciple while teaching his secret verse?
(a) Never to misuse the power achieved with the help of the verse
(b) Not to use it on the wild animals
(c) Not to share it with other disciples
(d) To practice it on animals before humans
(e) None of these
Ans: (a)

6. How did the other disciples react when the clever disciple decided to bring the tiger back to life?
(a) They felt jealous of him
(b) They all felt that it was a wise thing to do
(c) They felt sorry for the tiger
(d) They tried to stop him as he could put their lives in danger
(e) None of these
Ans: (d)

7. Why was the sage proud of his disciples?
(a) Because they had agreed to go to the forest for a long period of 40 days
(b) Because they had fought against the tiger very bravely
(c) Because they could bring the dead tiger back to life
(d) Because they were very bright and eager students
(e) None of these
Ans: (d)

8. Who/what is described as wicked and fierce by the author?
(a) The clever disciple
(b) The sage
(c) The tiger
(d) The forest
(e) None of these

Ans: (c)

9. Which of the following is NOT TRUE in the context of the passage?
(a) The clever disciple was brought back to life by the sage
(b) The sage wanted his disciples to use their learning only for doing good
(c) The sage was biased towards the clever disciple and disliked others
(d) The sage ultimately taught the secret verse to all his disciples
(e) All are true
Ans: (c)

10. Why did the clever disciple recite the verse to the dead tiger?
(a) So that the other disciples may be eaten up by the tiger
(b) To flaunt the power of the verse to the other disciples
(c) Because the sage told him to do so
(d) So that he could himself to the sage
(e) None of these
Ans: (b)

Directions—(Q. 11–13) choose the word that is MOST SIMILAR in MEANING to the word in bold letters.
11. PONDERED
(a) guessed
(b) puzzled
(c) studied
(d) thought
(e) attended
Ans: (d)

12. POUNCED
(a) climbed
(b) looked
(c) roared
(d) plunged
(e) jumped
Ans: (d)

13. CRIED
(a) wept
(b) screamed
(c) protested
(d) tearful
(e) saddened
Ans: (a)

Directions—(Q. 14 –15) choose the word which is MOST OPPOSITE in MEANING to the wordin bold letters.

14. BRIGHT
(a) dim
(b) soft
(c) dull
(d) faint
(e) vague

Ans: (c)

15. FIERCE
(a) timid
(b) emotional

Ans: (a)

Directions—(Q. 16 –20) Which of the phrases (a), (b), (c) and (d) given below each sentences should replace the phrase printed in bold in the sentence to make it grammatically correct ?
If the sentence is correct as it is given and No Correction is required, mark (e) as the answer.

16. He wants a start a new business but he did not have any money.
(a) Thought to start (b) Want to started (c) Wanted to start (d) Wants for start (e) No Correction Required

Ans: (c)

17. As Rohan was already late, he had his breakfast while walk down the road.
(a) walking down the (b) walking at the (c) walked on the (d) walked down the (e) No Correction Required

Ans: (a)

18. The poor bullock do not move since the cart was overloaded with heavy goods.
(a) cannot move (b) unable to move (c) was not moved (d) could not move (e) No Correction Required

Ans: (d)

19. He covered the expensive furniture at sheet before he started painting the ceiling.
(a) with sheet ahead (b) with sheet before (c) in sheet prior (d) in sheet earlier (e) No Correction Required

Ans: (b)

20. The smoke if inhaled proves to be more fatal than the burn itself.
(a) be most fatal (b) kill more fatal (c) be additional fatal (d) be greater fatal (e) No Correction Required

Ans: (e)

Friday, 3 July 2015

General Awareness Questions for Bank Exams - 11

General Awareness Questions for Bank Exams – 11

1. Who has been appointed the new Controller General of Accounts on July 1, 2012?

(a) Jawahar Thakur

(b) Neeraj Kumar

(d) Arun Mishra

Ans: (a)

2. Who is the author of the book ‘Beyond the lines’: An Auto Biography?

(a) Sharad Pawar

(b) Kushwant Singh

(d) General. J.J. Singh

Ans: (c)

3. NGRBA that was in news stands for:

(a) National Godavari River Basin Authority

(b) National Ganga River Basin Authority

(d) None of these

Ans: (b)

4. Who is the author of the book ‘ Turning Point – A journey through challenges’?

(a) A. P. J. Abdul Kalam

(b) Hamid Ansari

(d) Atal Bihari Vajpayee

Ans: (a)

5. Who has been awarded the World Food Prize in 2012?

(a) Kofi Annan

(b) Daniel Hillel

(d) Hillary Clinton

Ans: (b)

6. P.N. Dhar passed away on July 12, 2012 in New Delhi. He was a great –

(a) Poet

(b) Scientist

(d) Economist

Ans: (d)

7. Which part of India was included in World Heritage List by UNESCO on July 1, 2012?

(a) Eastern Ghats

(b) Western Ghats

(d) Konkan Railway

Ans: (b)

8. India’s first Mega Food Park became functional in 2012 at:

(a) Jaipur

(b) Kanpur

(d) Pune

Ans: (c)

9. Geeta Chaudhary is associated with:

(a) Boxing

(b) Wrestling

(d) Badminton

Ans: (c)

10. Who won the first medal for India in London Olympics in 2012?

(a) Abhinav Bindra

(b) Vijender Singh

(d) Sushil Kumar

Ans: (c)

11. Who is current Home Minister of India?

(a) P. Chidambaram

(b) Sushil Kumar Shinde

(d) Sharad Pawar

Ans: (c)

12. Which country first granted asylum to wikileaks founder Julien Assange?

(a) USA

(b) UK

(d) Germany

Ans: (c)

13. Captain Lakshmi Sehgal who passed away some time ago is:

(a) First Indian Airlines Pilot

(b) First MIG-21 fighter plane pilot

(d) Chief Minister of U.P.

Ans: (c)

14. One of the Asia-Pacific nations had agreed to hold its first ever maritime exercise with India. The nation is –

(a) Australia

(b) USA

(d) Vietnam

Ans: (b)

15. Francois Hollande was elected as President of which of the following nation?

(a) Poland

(b) Portugal

(d) Greece

Ans: (c)

Wednesday, 1 July 2015

TCS - 2015 Questions-1

TCS – 2015 Questions - 1

1. Given that 0 < a < b < c < d, which of the following the largest?
(a) (c+d) / (a+b)
(b) (a+d) / (b+c)
(c) b+c) / (a+d)
(d) (b+d) / (a+c)
Ans: (a)

These type of questions are best answered by apportioning values to the four alphabets.

Let ‘a’ be equal to 1, ‘b’ 2, ‘c’ 3 and ‘d’ 4. Apportioning these values we observe that option (a) is the largest.

* * * 7 * * * X * * * 8 * *

The fourteen digits of a credit card are to be written in the boxes shown above. If the sum of every three consecutive digits is 18, then the value of x is :
(a) 3
(b) cannot be determined from the given information.
(c) 2
(d) 1
Ans: (a)

The sum of each three squares is 18. Starting from the left we have four sets of three squares.

Let the last two squares be A and B.

Now we have the total sum of all the squares as -> 18*4 + A + B -> 72 + A + B ………. (i)

Excluding the squares having digits 7, X and 8 we have three sets of three squares.

The total sum of these squares is -> 3*18 + 7 + X + 8 + A + B -> 69 + X + A + B ……….. (ii)

Solving (i) and (ii) we get the value of ‘X’ as 3.

3. Jake can dig a well in 16 days. Paul can dig the same well in 24 days. Jake, Paul and Hari together dig the well in 8 days. Hari alone can dig the well in
(a) 96 days
(b) 48 days
(c) 32 days
(d) 24 days
Ans: (b)

Jake in one day can do 1/16 work. In 8 days he can do 8/16 -> ½ work

Paul in one day can do 1/24 work. In 8 days he can do 8/24 -> 1/3 work.

Hari in one day can do 1/H work and in 8 days can do 8/H work.

Thus we have an equation : ½ + 1/3 + 8/H = 1

8/H = 1 – (1/2 + 1/3). 8/H = 1/6 -> H = 48. Thus Hari will take 48 days to complete the work.

4. The sum of the digits of a three digit number is 17, and the sum of the squares of its digits is

109. If we subtract 495 from the number, we shall get a number consisting of the same digits written in the reverse order. Find the number.
(a) 773
(b) 683
(c) 944
(d) 863
Ans: (d)

The two points to note here are (i) the sum of the squares is 109 and (ii) and after subtracting 495 the digits are the same in the reverse order. Hence, we can answer this question from the options given.

Only option (b) and (d) fulfil the first condition. But, option (ii) fulfils both the conditions.

Hence the answer is (d) 863.

5. Mark told John "If you give me half your money I will have Rs.75. John said, "if you give me

one third of your money, I will have Rs.75/- How much money did John have ?
(a) 45
(b) 60
(c) 48
(d)37.5
Ans: (b)

Let M and J be the initial money that the two have.

We now have two equations:

M + J/2 = 75 => 2M + J = 150 …….. (i)

M/3 + J = 75 => M + 3J = 225 …….. (ii)

Multiplying (ii) by 2 we get -> 2M + 6J = 450 …….. (iii)

Subtracting (i) from (iii) we get 5J = 300 and J = 60

6. Eesha has a wheat business. She purchases wheat from a local wholesaler of a particular

cost per pound. The price of the wheat of her stores is $3 per kg. Her faulty spring balance reads 0.9 kg for a KG. Also in the festival season, she gives a 10% discount on the wheat. She found that she made neither a profit nor a loss in the festival season. At what price did Eesha purchase the wheat from the wholesaler?
(a) 3
(b) 2.5
(c) 2.43
(d) 2.7
Ans: (c)

Since her spring balance is faulty sale of 1 kg is shown as 0.9kg and thus she loses 10% on the sale price and gets only Rs 2.70 per kg.

Further, she allows additional 10% discount on this price and thus she gets only Rs 2.43 per kg.

At this price there is no gain or loss for her. Hence her purchase price is Rs 2.43 per kg.

7. Raj goes to market to buy oranges. If he can bargain and reduce the price per orange by

Rs.2, he can buy 30 oranges instead of 20 oranges with the money he has. How much money does he have?
(a) Rs.100
(b) Rs.50
(c) Rs.150
(d) Rs.120
Ans: (d)

Let M be the money that Raj has. Then we have an equation

M/20 – M/30 = 2. Solving we get the value of M as Rs 120.

8. A city in the US has a basketball league with three basketball teams, the Aziecs, the Braves and the Celtics. A sports writer notices that the tallest player of the Aziecs is shorter than the shortest player of the Braves. The shortest of the Celtics is shorter than the shortest of the Aziecs, while the tallest of the Braves is shorter than the tallest of the Celtics. The tallest of the Braves is taller than the tallest of the Aziecs.
Which of the following can be judged with certainty?
(X) Paul, a Brave is taller than David, an Aziec
(Y) David, a Celtic, is shorter than Edward, an Aziec
(a) Both X and Y
(b) X only
(c) Y only
(d) Neither X nor Y
Ans: (b)

Let us take the height of the shortest of the Braves as 4 ft. Then the tallest of the Aziecs is less than these heights say 3 ft. Now we can arrive at the range of heights of the three teams.

Aziecs height range from 2 – 3

Braves height range from 4 – 6

Celtics height range from 1 – 7

We can now conclude that X is correct while Y cannot be determined.

9. There are 3 classes having 20, 24 and 30 students respectively having average marks in
an examination as 20,25 and 30 respectively. The three classes are represented by A, B and C and you have the following information about the three classes.
(i) In class A highest score is 22 and lowest score is 18
(ii) In class B highest score is 31 and lowest score is 23
(iii) In class C highest score is 33 and lowest score is 26.
If five students are transferred from A to B, what can be said about the average score of A; and what will happen to the average score of C in a transfer of 5 students from B to C ?
(a) definite decrease in both cases
(b) can't be determined in both cases
(c) definite increase in both cases
(d) will remain constant in both cases
Ans: (b)
Class A average is 20. And their range is 18 to 22
Class B average is 25. And their range is 23 to 31
Class A average is 30. And their range is 26 to 33
If 5 students transferred from A to B, A's average cannot be determined but B's average comes down as the highest score of A is less than lowest score of B.
If 5 students transferred from B to C, C's average cannot be determined the B's range of marks and C's range of marks are overlapping.

10. The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 3 years?
(a) Rs.13435
(b) Rs.23125
(c) Rs.19000
(d) Rs.16875
Ans: (d)
40000 * (3/4)³ = 16875.