TCS-Questions-2

TCS Questions-2TCS Questions – 2

1.    If the sum of each row, each column and each diagonal are the same then, find the value of ( Y + Z ).

V	50	W
196	X	Y
269	Z	123

There are two possible way of arriving at the solution.

269 + 196 + V = V + 50 + W.  Cancelling out V on both sides we can arrive at the value of W as 415. Likewise

269 + 196 + V = 123 + X + V. Again cancelling out V on both sides we get the value of X as 342. Now we have the total of one diagonal as 269 + 342 + 415 = 1026. It is now easy to arrive at the value of the other alphabets:  V = 561, Y = 488, and Z = 634.

Hence the value of Y + Z = 488 + 634 = 1122

		Z
	V		W
Y		X		196
	269		123
		50

Re-arrange the grid in the following manner. You will be surprised to find the difference between each two digits is 73. This is one simple way of solving 3 x 3 grid Sudoku type questions.

The value of X will be 269 + 73 = 342

The value of W will be 342 + 73 = 415

The value of Y will be 415 + 73 = 488

The value of V will be 488 + 73 = 561

The value of Z will be 561 + 73 = 634

2.    Please find the value of ( Y + Z ) in the following grid.

V	-16	W
-2	X	Y
5	Z	-9

The difference between the digits is 7 and going by either of the two methods mentioned earlier the

Answer is 66

3.    Find the value of 7*A + 7*B + 6*C*D in the following simple subtraction where some digits are represented by Alphabets.

    A  7  C  2

-        4  B  6  8

 5  4   3  D

                                                                     ---------------

Proceed from the final value and move upwards. You will get the values for A-9, B-2,

C- 0 and D- 4.  Answer is 77.

4.    What is the reminder when 50! Is divided by 16^15?

The answer is 1. 16^15 can be written as (2^4)^15. Ie  2 ^ 60.  In 50! All factorials after 2! Are divisible by 2 and only 1! is not divisible by 2. Hence the answer is 1.

5.    What is the value of the 30^th term in the following series:

1, 5, 6, 25, 26, 30, 31, 125, 126, 130, 131, 150, 151, 156, ……….

Answer is 780.  If you look at the pattern of the series you will note the first term multiplied by 5 gives the second term, the second term multiplied by 5 gives the fourth term, the fourth term multiplied by 5 gives the 8^th term and so on. Hence the 30^th term is obtained by multiplying the 15^th term by 5. (156 x 5 = 780)

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