State Bank of India - Selective Questions - 2

State Bank of India – Selective Questions - 2

1.       Bala buys an equal number of pens, pencils, and sketch pens costing Rs.2.50, Rs.3, and Rs.5 respectively. How many of each did he buy if he spends totally Rs.168?
a)12                       b)16                       c)18                        d)20
Ans:  (b)

Let ‘x’ be the number of Pens, Pencils and Sketch Pens purchased by Bala.

Then we have an equation (2.50)*x + 3*x + 5*x = 168.

Solving we get the value of ‘x’ as 16.  

2.       Prabha and Aarthi paid a total of Rs.600 for some goods. If Prabha paid 120 more than that of Aarthi, then how much is already paid by Aarthi?
a)Rs.250               b)Rs.150               c)RS.550               d)Rs.240
Ans:  (d)

Let the amount paid by Aarthi be ‘x’. Then we have an equation  x + (x+120) = 600.

Solving we get the value of ‘x’ as Rs 240.00

3.       A fruit seller had some apples. He sells 30% apples at the rate of Rs.30 per apple and the remaining 315 apples at the rate of Rs.20 per apple. The total amount realized by him is how much?
a)Rs.15900          b)Rs.10350          c)RS.11550          d)Rs.12420
Ans: (b)

He sold 30% of apples at Rs 30/- per apple and the remaining 315 apples at Rs 20/- per apple. We now know the remaining 70% apples amounts to 315. Hence the 30% apples he sold were 135 in numbers. Now applying the price at which he sold them, we have

(135 x 30 = 4050) + (315 x 20 = 6300) -> 10350.

4.       Devi buys some material worth Rs. X. She gets a deduction of Rs.650 on it. After getting deduction she pays tax of Rs.169. Then find X the value if she pays Rs.6000 for that material.
a)Rs.6481             b)Rs.5689            c)RS.6819             d)Rs.5181
Ans : (a)

Let ‘x’ be the price of the material. Then from the given information we have one simple equation ->  x – 650 + 169 = 6000. Solving we get the value of ‘x’ as RS 6481

5.       If two-third of two-seventh of a number is 60, then two-fifteenth of that number is
a)60                       b)42                       c)315                     d)21
Ans: (b)

2/3 * 2/7 = 60. Hence the whole number is 60 * 21/4 = 315.

2/15 of 315 is 315 * 2/15 = 42.

6.       Two times of the third of three consecutive even integers is three times of the first. Then the second integer is:
a)60                       b)42                       c)10                        d)12
Ans: (c)

Let the three consecutive even numbers be  x, x+2, and x+4

We are informed two times of the third is equal to three times of the first

Thus 2(x+4) = 3x. Solving we get ‘x’ equal to 8. The second number is x+2 = 8+2 -> 10.

7.       Find the integer which when decreased by 2 is 80 times the reciprocal of the same number
a)60                       b)42                       c)10                        d)12
Ans:  (c)

Let ‘x’ be the integer. Then we have an equation x-2 = 80 (1/x) -> x-2 = 80/x

Combining both we have x² – 2x – 80 = 0. This can be written as (x-10)(x+8)

The value of ’x’ can either be 10 or -8. Since the value cannot be negative the value of the integer is 10.

8.       Four of the following five are alike in a certain way and so form a group. Which is the one that does not belong to the group?
(a) 115                  (b) 145                  (c) 95                     (d) 155                  (e) 75
Ans: (e)

75 is the only number that is divisible by 3.

9.       How many meaningful words can be made from the letters ADEL using each letter only once?
(a) None              (b) One                                (c) Two                 (d) Three             (e) More than three
Ans: (d)  (The words are LEAD, LADE and DEAL)

10.   How many such pairs of letters are there in the word "ADVERTISE', each of which has as many letters between them in the word, as they have in the English alphabet?
(a) None              (b) One                                (c) Two                 (d) Three             (e) More than three

Ans: (b)  Letters D and I