State Bank of India - Selective Questions - 3

State Bank of India – Selective Questions - 3

1.       In how many different ways can the letters of the word 'FLEECED' be arranged ?
(a) 840         (b) 2520                (c) 1680                (d) 49                    (e) None of these

Ans: (a)     7!

2.       Arul was going to market from his home. He walked 4 Km to the north, turned right and walked 3 Km. He then turned left and walked 4 Km. Then he took a left and walked till he reached the market which was exactly to the east of his house. Find the distance of the market from his home along north.

Ans: 8 km. ( The question is meant to confuse. From the house Arul walks totally 8 km North. The Market is towards East of his house but at what distance is not given. Only the distance along North from his house is asked. Hence the answer is 8 km.)

3.       Starting from his house, Rahul walked 5 Km to the north east to reach a shop. From there he took a right and walked another 5 Km to reach his friend’s house. How far is his friend's house from his house (along eastern direction)?

Ans: √50

4.       Once economically sound city introduced a series of reform measures to _____ the economy.
(a) improve                               (b) revive            (c) hurt                 (d) encourage

Ans: (b) (Confusion may arise as to whether (a) or (b) is the answer. The question talks about    once economically sound city. Hence ‘Revive’ would be the right answer).

5.       Wounds go away but deep _____ may turn permanent.
(a) Worries                                (b) Pain                                (c) Cuts                 (d) Scars

Ans: (d)  ( Here the confusion will be between ‘Cuts’ and ‘Scars’. Deep cuts over a priod are likely to disappear while the Scars remain permanent. In the context of the question ‘Scars’ would be an appropriate answer.

6.        ______ packets of a popular shampoo are being distributed free to people in this apartment as a part of advertisement/promotion exercise.
(a) Large                     (b) Sample          (c) Fortified        (d) Extra

Ans: (b)  (Normally in all advertisement/promotional activities sample packets are generally given)

7.       A train of length 150 meters can cross a bridge in 30 seconds when travelling at a speed of 40km/hr. Then what is the length of the bridge?
(a) 180m                     (b) 182m              (c) 183m               (d) 185m

Ans: (c)

The speed of the train is 40 kmph. Or 40 *5/18 = 100/9 mtrs/sec.

The train crosses the bridge in 30 seconds. Thus the distance travelled in 30 seconds is 3000/9 or 1000/3 meters -> 333.33meters. The length of the train is 150 meters.

Hence the length of the bridge is 333.33 – 150 -> 183.33 meters -> 183 meters.

8.       A train crosses a bridge and a bike standing on the bridge in 40 seconds, 25 seconds respectively. What is the length of the bridge if the speed of the train is 50.4km/hr?
(a) 180m                     (b) 210                  (c) 183                   (d) 185

Ans: (b)

The speed of the train is 50.4 kmph. Or 50.4 * 5/18 -> 14 meters/sec.

The train crosses the bridge in 40 seconds. Hence the distance travelled in 40 seconds is 14 * 40 -> 560 meters. ( The train travelled its length and the bridge length)

The train crossed the bike on the bridge in 25 seconds. Distance travelled in 25 seconds -> 14 * 25 -> 350 meters ( The train’s length)

Hence, the length of the bridge is 560 – 350 -> 210 meters.

9.    In what time a train 120 meters long travelling at a speed of 70km/hr crosses a cyclist who is at                 the speed 5km/hr in the direction opposite to the train?
       (a)  4.76sec                  (b)   5.76sec        (c)   8.92sec         (d)  6.14sec

       Ans:  (b)

The Train and the Cyclist are moving in opposite directions at speeds of 70 kmph and 5 kmph     respectively. Hence the relative speed is 70 + 5 = 75 kmph -> 75 * 5/18 -> 125/6 meters/second.

The train of length 120 meters has to travel its length to cross the cyclist. Hence the time taken to cross is 120/ (125/6) = 5.76 seconds.