Infosys Reasoning (Recent) - 4

Infosys Reasoning (Recent) - 4

1.       There are 2 persons each having the same amount of marbles in the beginning. After that one person gain 20 more from the other person and he eventually lose two third of it during the play.  The second person now has 4 times the marbles the first person is now having. Find out how much marble did each had in the beginning.
Ans: Each had 100 marbles.
Let ‘x’ be the number of marbles each had initially.

First person gains 20. He now has (x + 20) marbles. He loses 2/3 of it during the play.

Hence the first person now has only 1/3(x+20) marbles.

The second person after losing 20 has (x-20) marbles. After gaining 2/3 of marbles from first person during play now has (x-20) + 2/3(x+20) marbles.

It is said the second person now has four times the number of marbles the first person has.

Thus we have an equation:   4 * 1/3(x+20) = (x-20) + 2/3(x+20)

Solving we get the value of ‘x’ as 100.

2.       There are certain diamonds in a shop. The first thief came and stole half of the diamonds plus 2. The second thief came and stole half of the remaining plus 2. The third thief came and he also stole half of the remaining diamonds plus 2. When the fourth thief came and stole half of the remaining plus 2 there remained no diamond. How many diamonds were there originally?

Ans: 60 Diamonds.

Let ‘x’ be the total number of diamonds initially.

First thief stole Half plus 2 ->   x/2 – 2 …….. Let this be A

Second thief stole half of remaining plus 2  ->  A/2 – 2 …….. B

Third thief stole half of remaining plus 2  ->  B/2 -2 …………..C

Fourth thief stole half of remaining plus 2 and there remained Nil diamonds.

Now going up from the last thief we have ->  C/2 – 2 = 0. Hence, C = 4

B/2 – 2 = 4. Hence, B = 12

A/2  - 2 = 12. Hence A = 28.

x/2 – 2 = 28. Hence ‘x’ = 60.

3.       There are three friends A B C.
1. Either A or B is oldest.
2. Either C is oldest or A is youngest.
Who is Youngest and who is Oldest?
Ans:  A is youngest and B is oldest.

4.       Father says my son is five times older than my daughter. My wife is 5 times older than my son. I am twice as old as my wife and together (sum of our ages) is equal to my mother 's age and she is celebrating her 81 birthday. So what is my son's age?
Ans: 5 years.

Let the Daughter’s age be ‘x’. Then the Son’s age is 5x. The mother’s age is 5 * 5x = 25x.

I am twice the age of my wife and so, I am 2 * 25x = 50x. The sum of our ages is equal to my mother’s age which is 81. So, we now have an equation

X + 5x + 25x + 50x = 81 -> 81x = 81 and ‘x’ = 1.

My son’s age 5x = 5

5.       In Mulund, the shoe store is closed every Monday, the boutique is closed every Tuesday, the grocery store is closed every Thursday and the bank is open only on Monday, Wednesday and Friday. Everything is closed on Sunday.
One day A, B, C and D went shopping together, each with a different place to go. They made the following statements:
A. D and I wanted to go earlier in the week but there wasn’t a day when we could both take care of our errands.
B. I did not want to come today but tomorrow I will not be able to do what I want to do.
C. I could have gone yesterday or the day before just as well as today.
D. Either yesterday or tomorrow would have suited me.
Which place did each person visit?
Ans:  A-BOUTIQUE
          B-BANK
          C-GROCERY
          D-SHOE

6.       Five hunters Doe, Deer, Hare, Boar and Row kill 5 animals. Each hunter kills an animal that does not correspond to his name. Also each hunter misses a different animal which again does not correspond to his name.
a) The Deer is killed by the hunter, known by the name of the animal killed by Boar.
b) Doe is killed by the hunter, known by name of animal missed by Hare.
c) The Deer was disappointed to kill only a Hare and missed the Roe.

Name the animals killed and missed by the five hunters.

Ans:

 
Doe killed Deer and missed Hare. 
Hare killed Roe and missed Boar. 
Roe killed Boar and missed Doe. 
Boar killed Doe and missed Deer.

7.       A person needs 6 steps to cover a distance of one slab. If he increases his foot length (step length) by 3 inches he needs only 5 steps to cover the slabs length. What is the length of the each slab?
Ans:  90 inches.

Let ‘x’ be the distance of each step. Then the length of the slab -> 6x

Now the step length is increased by 3”. The new step length is (x + 3)

The length of the slab now is -> 5 (x+3) Since the slab length is the same we have

6x = 5 (x+3) Solving we get the value of ‘x’ as 15 and the length of the slab 90 innches.

8.       There is one lily in the pond on 1st June. There are two in the pond on 2nd June, four on the 3^rd June, eight on 4^th June and so on. The pond is full of lilies by the end of June.  

i)                    On which date the pond is half full?
Ans: 29th. (The month of June has 30 days).

ii)                   If we start with 2 lilies on 1st June, then when will the pond be full with lilies?
Ans: 29th June.

9.       a) 10 1 9 2 8 3 7 4 6 5 5 6 4 7 3 8 2 _ _
Ans: 9, 1

10.   From a vessel, 1/3rd of the liquid evaporates on the first day. On the second day 3/4th of the remaining liquid evaporates. What fraction of the volume is present at the end of the second day?
Ans:  1/6 of the original volume.

Let as assume the original volume as 300 ml. (for easy working)

On the first day 1/3 evaporates ie. 100 ml is evaporated. Remaining is 200 ml.

On the second day ¾ of this is evaporated ie 150 ml is evaporated and

Remaining is 50 ml which is 1/6^th of the original volume.