Infosys – Verbal
& Reasoning
Directions 1- 8: In each question, a part of sentence is
printed in italics. Below each sentence, some phrases are given which can
substitute the italicized part of the sentence. If the sentence is correct as
it is, the answer is 'No correction required'
1. He did many mischiefs
1. He did many mischiefs
a) made many a
mischiefs b)
made much mischief
c) Committed many mischiefs d) No Correction required
Ans: (c)
c) Committed many mischiefs d) No Correction required
Ans: (c)
2. Rohit
is as fast as or perhaps faster than
Manish.
a) Equally fast b) almost as fast c) as fast d) No Correction required
a) Equally fast b) almost as fast c) as fast d) No Correction required
Ans: (d)
3. All
his family members are in Kanpur.
a) All of his family members
a) All of his family members
b) All the family members if
his
c). All the members of his family
d). No Correction required
Ans: (c)
c). All the members of his family
d). No Correction required
Ans: (c)
4. I often see him dancing the top
a) rotating
b) encircling
c) dodging
d) No Correction required
Ans: (d)
a) rotating
b) encircling
c) dodging
d) No Correction required
Ans: (d)
5. What is the time in your watch?
a) on b) by c) from d) No Correction required
Ans: (c)
a) on b) by c) from d) No Correction required
Ans: (c)
6. Columbus invented America
a) searched b) traced c) discovered d) No Correction required
Ans: (c)
a) searched b) traced c) discovered d) No Correction required
Ans: (c)
7. Wise men catch time by the forelock.
a)
Hold b)
seize c)
take d) No Correction required
Ans: (c)
Ans: (c)
8. A bird in hand is worth two in bush
a) two in the bush b) two at a bush c) two on bush d) No Correction required
Ans: (a)
a) two in the bush b) two at a bush c) two on bush d) No Correction required
Ans: (a)
Reasoning Questions:
1. A boy asks his father, "What is the age of grand-
father?". Father replied " He is x years old in x^2 years", and
also said, "we are talking about 20th century". What is the
year of birth of grand- father?
Ans: 1892.
The clue for this question is
“we are talking about the 20th century”. Hence the grand-fathers present age should be
between 1901 – 1999. Further it is said the grand-father will be x years in x^2
years.
Let us assume x = 43
years. Then x^2 will be 1849.
If x = 44 years then x^2 will be 1936.
If x is 45 years then x^2 will be 2025. Of these three only 44 years fits in the
conditions given.
Hence the grand-father age is
44 years and he was born in 1936 – 44 -> 1892.
2. A boy travels in a scooter and after covering 2/3rd of the
distance the wheel got punctured. He covered the remaining distance by walk. The
walking time was twice that of the boy’s riding time. The
riding speed was how many times that of the walking speed?
Ans: 4 times.
A simple question. If the time taken for riding in the scooter was 1 hour then the time taken for walking was 2 hours.
Ans: 4 times.
A simple question. If the time taken for riding in the scooter was 1 hour then the time taken for walking was 2 hours.
The
boy takes 2 hours to walk the distance of 1/3. So to walk the distance of 2/3
he would have taken 4 hours. Thus the riding speed was 4 times the walking
speed.
3. A man sold 2 pens the initial cost of each was Rs. 12. If
he sells them together one at 25% profit and another at 20% loss find the
amount of his loss or gain.
Ans: 60 Paise gain
The
total cost of two pens -> 12 x 2 = Rs
24.
The
sale price on selling one pen at 25% profit -> 12 * 125/100 -> Rs 15.00
The
sale price on selling one pen at 20% loss
-> 12 * 80/100 ->
Rs 9.60
The
total sale price -> 15 + 9.60 ->
Rs 24.60
Gain
0.60 paise.
4. Find the 3 digit no. whose last digit is the square root of
the first digit and second digit is the sum of the other two digits.
Ans: 462 (The answer could also be 121)
Ans: 462 (The answer could also be 121)
5. Meera was playing with her brother using 55 blocks. She
gets bored playing and starts arranging the blocks such that the no. of blocks
in each row is one less than that in the lower row. Find how many were there in
the bottom most row?
Ans: 10 (Clue : The sum of digits from 1 to 10 is 55)
Ans: 10 (Clue : The sum of digits from 1 to 10 is 55)
6. Three persons A, B &C went for a robbery in different
directions and they theive one horse, one mule and one camel. They were caught
by the police and when interrogated gave the following statements
A: B has stolen the horse
B: I didn't rob anything.
C: both A & B are false and B has stolen the mule.
The person who has stolen the horse always tells the truth and
the person who has stolen the camel always tell the lie.
Find who has stolen which animal?
Ans:
A- camel
B- mule
C- horse
A: B has stolen the horse
B: I didn't rob anything.
C: both A & B are false and B has stolen the mule.
The person who has stolen the horse always tells the truth and
the person who has stolen the camel always tell the lie.
Find who has stolen which animal?
Ans:
A- camel
B- mule
C- horse
If A
is telling the truth then B has stolen Horse. The one who has stolen the Horse
always tell the truth. But, B says he didn’t rob anything. Thus it would
confirm that both A and B are lying and C alone is telling the truth.
7. A, B, C, D & E
are having their birthdays on consecutive days of the week not necessarily in
the same order. A 's birthday comes before G's as many days as B's birthday
comes after E's. D is older than E by 2 days. This time G's birthday came on Wednesday.
Then find the day of each of their birthdays?
Ans:
Birthday of D on SUNDAY
Birthday of B on MONDAY
Birthday of E on TUESDAY
Birthday of G on WEDNESDAY
Birthday of A on THURSDAY
Ans:
Birthday of D on SUNDAY
Birthday of B on MONDAY
Birthday of E on TUESDAY
Birthday of G on WEDNESDAY
Birthday of A on THURSDAY
8. A girl 'A' told to her friend about the size and colour of
a snake she has seen in the beach. It is one of the colours brown/black/green and
one of the sizes 35/45/55.
If it were not green or if it were not of length 35 it is 55.
If it were not black or if it were not of length 45 it is 55.
If it were not black or if it were not of length 35 it is 55.
a) What is the colour of the snake?
b) What is the length of the snake?
Ans:
a) brown
b) 55
If it were not green or if it were not of length 35 it is 55.
If it were not black or if it were not of length 45 it is 55.
If it were not black or if it were not of length 35 it is 55.
a) What is the colour of the snake?
b) What is the length of the snake?
Ans:
a) brown
b) 55
9. After World War II three departments did as follows First
department gave some tanks to 2nd &3rd departments equal to the number they
are having. Then 2nd department gave some tanks to 1st & 3rd departments
equal to the number they are having. Then 3rd department gave some tanks to 2nd
&1st departments equal to the number they are having. Then each department
has 24 tanks. Find the initial number of tanks of each department?
Ans : A-39 B-21 C-12
Ans : A-39 B-21 C-12
Let us start from the last
transaction.
C gives to A and B equal
number of tanks that they have. After this all the three have 24 tanks. In
other words both A and B were having 12 tanks each prior to getting from C.
Hence we know that C had 48 tanks before giving to A and B.
Now coming to B, both C and A
receives an equal number of tanks they had. After receiving from B, C had 48
tanks. Hence it is evident B gave C 24 tanks. Before C giving A had 12 tanks
that includes tanks received from B. B gave an equal number of tanks to A.
Hence A was having only 6 tanks before getting from B. It now transpires B
should have had 12 + 6 + 24 (the final number left over) -> 42 tanks.
Now A gave B and C equal
number of tanks they had. Thus A gave B 21 tanks and C 12 tanks leaving a
balance of 6 tanks.
Hence, initially A has -> 6
+ 21 + 12 = 39 tanks.
B has 21 tanks and C 12 tanks
making a total of 72 tanks.
10. A lady was out for shopping. She spent half of her money in
buying A and gave 1 dollar to a beggar. Further she spent half of her remaining money
and gave 2 dollar to charity. Further she spent half of remaining money and
gave 3 dollar to some children. Now she is left with 1 dollar. How much she had
in the beginning?
Ans: $42.
Let ‘x’ be the amount the lady had initially.
Let ‘x’ be the amount the lady had initially.
1st
transaction -> x/2 – 1 let the
reminder be ‘A’.
2nd
transaction -> A/2 – 2 let the
reminder be ‘B’
3rd
transaction -> B/2 – 3 = 1
Now
solving the 3rd transaction we get the value of ‘B’ as 8
Solving
the 2nd transaction we get the value of ‘A’ as 20
Solving
the 1st transaction we get the value of ‘x’ as 42. (Initial amount
she had)
No comments:
Post a Comment