Aptitude Questions -1 (culled from
different IT company papers)
1.
A
starts from a place at 11.00 a.m. and proceeds at a speed of 4 kmph. B starts
at 1 p.m. with initial speed of 1 kmph and increases his speed every hour. At
what time will B catch up with A?
Answer: 9.48 p.m.
A
starts at 11.00 a.m. B starts at
1.p.m.
@
12 noon A
will be at 4 km B not
yet started.
@ 1.00 p.m.
“ 8 km B just starts
@ 2.00 p.m. “ 12 km B will be at 1 km
@
3.00 p.m. “
16 km B
“ 3 km ( B increases his
Speed
by 1 km)
@
4.00 p.m. “ 20 km B
“ 6 km
Likewise
@
9.00 p.m. “ 40 km B
“ 36 km
Hence
between 9 and 10 p.m. B will catch A. At
9 P.m. B ‘s speed was 8 kmph and between 9 p.m. and 10 p.m. his speed will be 9
kmph. A’s sped continues to remain at 4kmph.
So
the relative speed between B and A at this time is 5 kmph. At 9.00 p.m. A is
ahead of B by 4 km. Hence to catch up with him B will take 4 / 5 hours.
Ie
0.8 hours or 48 minutes. Hence B will catch up with A at 9.48 p.m.
2.
Working
independently Tina and Ann could finish a job in 12 hours and 9 hours
respectively. If Tina works on the job independently for 8 hours and then Ann
starts working independently on the same job, in how much time would Ann
complete the job?
Answer: 3 hours.
Tina
takes 12 hours to complete the job. In one hour she does 1/12 job and in 8
hours she had completed 8/12 = 2/3 job.
Hence
remaining job is 1/3.
Ann
takes 9 hours to complete a job. So, in one hour she does 1/9 job.
For
completing th remaining 1/3 job she will take
(1/3) / (1/9) = 3 hours.
3.
If
a = 2, b = 4 and c = 5 then what is a + b / c
- c/a + b.
Answer: 11/30
This question had confused a few since the official answer was not
tallying with their working.
Actually
the question if looked at as (a + b) / c
- c / (a + b) would give you the
right answer.
4.
10^2
(10^8 + 10^8) =10^4 x ? ( I have
reframed the question so that there is no confusion in the mind of the
students)
Answer: 2 * 10^6
10^2
* 2(10^8) = 2 * 10^2 x 10^8 = 2 * 10^10. Hence
2 * 10^10 = 10^4 x 2 * 10^6
5.
The
maximum number of students among whom 1001 pens and 910 pencils can be
distributed in such a way that each student get the same number of pens and
pencils is:
Answer: 91 (Simple
logic: HCF of 1001 and 910 )
6.
The
total population of a town was 8000. In one year the population increased by
9%.However, the Male population increased by 10% and the female population
increased by 8%. How many males were there in the town initially?
Answer: 4000
Let
the male population be x and female population be y. We know that x + y = 8000
Hence
the female population y = 8000-x.
The
men increases by 10% and the women increases by 8% and the total population
increases by 9%.
So,
we have an equation
x
+ 10x / 100 + (8000 – x) +8(8000-x)/100 = 8000 + 8000 x 9/100
Working out you will get the value of
x as 4000.
7.
1000
boys and 800 girls took an examination. 60% of the boys an 50% of the girls
passed the examination. What is he percentage of students who have not passed
the examination?
Answer: 44.44%
Out
of 1000 boys 60% passed ie 600 students. No. of boys failed 400
Out
of 800 girls 50% passed ie 400 students. No. of girls failed 400.
Total
number of students failed is 800 out of total number students appeared 1800
Hence percentage of students failed is
800*100/1800 = 44.44%
8.
A
company contracts to paint three houses. Mr Brown can paint a house in 6 days.
Mr Black would take 8 days while Mr Blue will take 12 days to paint the house.
Mr Brown starts the work and continues for 8 days and then leaves. Mr Black
takes up the work, and works or 6 days and leaves. Now Mr Blue will be
completing the contract in how many days?
Answer: 11 days.
Total
job to be completed under the contract is 3 (houses)
Mr
Brown in 1 day can do 1/6 job. So, in 8 days has done 8/6 or 4/3 job.
Mr
Black in one day can do 1/8 job and in 6 days does 6/8 or ¾ job.
So
Mr Brown and Mr Black together have completed 4/3 + ¾ = 25/12 job or 2 and 1/12
job. The remaining job is 11/12.
Mr Blue in one day can do 1/12 job and
for completing the remaining 11/12 job would take 11 days.
9.
Two
hours after a freight train leaves Delhi, a passenger train starts from the
same station and in the same direction at a speed of 60 kmph. The passenger
train overtakes the freight train in four hours. What is the speed of the
freight train?
Answer: 40 kmph
A simple sum. In 4 hours the passenger train
would have travelled 4*60=240 kms
The
freight train left 2 hours earlier than the passenger train. Hence to travel
this distance of 240 kms, the freight train hd taken 2 + 4 = 6 hours.
Hence the speed of the freight train
was 240 / 6 = 40 kmph.
10. A man fixed an appointment to meet the
Manager. The Manager asked him to come two days after the day before the day
after tomorrow. If today is Friday, then on what day the Manager fixed the
appointment?
Answer: Monday. (Simple logic. Please
note that this is a repeat question in many papers)
---
x ---
No comments:
Post a Comment