TCS Questions – 6
1.
If
the ticket sales ‘S’ of a company increases by 25% from standard sales to 60
tickets sold, then what is the value of 60 – S?
Answer: 12
The
normal sales is S. From the question it is noted that S + 25%S = 60
ie 5/4 S = 60 Hence S value is 48.
60
– 48 = 12.
2.
In
a certain department store there are four sizes of specific shirts. It has 1/3 as
many small shirts as medium shirts. It also has ½ as many large shirts as small
shirts. If the store were to have as many x-large shirts as large shirts, then
what is the percentage of medium shirts in the store? (I have reframed the
question for better understanding)
Answer: 60%
Let
S be small shirts, M medium shirts, L large shirts and X x-large shirts
Then
from the information we have the following:
S
= M/3. L = S/2 = M/3x2 = M/6.
Since L = X we note that X = M/6
Total
shirts in the stores is S + M + L +
X substituting the respective values we
get
The
total number of shirts as M/3 + M + M/6 + M/6
= 5M/3
Percentage
of Medium shirts to total shirts is M/(5M/3)
x 100 =
60%
3.
A
computer store regularly sells all stock at a discount of 20% to 40%. If an
additional discount of 25% is allowed on the discounted price during a special
sale, what would be the lowest possible price of a part costing $16?
Answer: $7.20
The
original cost is $16 and the lowest price would be at maximum discount of 40%.
After
this discount the cost of the part comes down to $9.60. An additional discount
of 25% is allowed on this price. So the lowest possible price for the part
would be
$9.60 - $ 2.40 = $7.20.
4.
The
owner of a hobby store needed to calculate the percentage of customers who purchase
wood glue. On completion of a survey, he observed that 60% of the people who
entered the stores purchased an item and 15% of them purchased wood glue. What
percentage of people who entered the store purchased wood glue?
Answer: 9%.
These type of questions are best answered
assuming a convenient figure to start. Let us assume 100 people entered the
store. Of these 60 people purchased an item. 15% of the 60 people purchased
wood glue.
Hence
percentage of people who purchased wood glue is (15 x 60)/100 ie 9%
5.
From
7 A.M. to 11 A.M. it rained 2.25 inches. From 11 A.M. the falling of rain
increased to 1.25 inches every two hours. How many inches of rain had fallen at
5 P.M. that day?
Answer: 9.75 inches.
Up
to 11 A.M. the amount of rain fallen was 2.25 inches. Between 11 A.M and 5 P.M.
the time difference is 6 hours. The rain fall was increasing at the rate of
1.25 inches every two hours.
Between
11 A.M. and 1 P.M. the rain fall was 1.25 inches.
From
1 P.M. to 3 P.M. the rain fall
was 2.50 inches
From
3 P.M. to 5 P.M the rain fall
was 3.75 inches
Thus
the total rain fall from 11 A.M. to 5 P.M. was 7.50 inches. Up to11 A.M. it was
2.25 inches. Hence the total rain fall
from 7 A.M. to 5 P.M. was 9.75 inches.
6.
Pradeep
combines two mixtures of milk and water. He mixes the first mixture of 40 litres
containing 20% water with second mixture of 60 litres containing 30% water.
What is the percentage of water in the combined mixtures of milk and water?
Answer: 26%
Quantity
of water in 40 litres mixture is 20%
ie (40 x 20) / 100 = 8 litres
Quantity
of water in 60 litres mixture is 30%
ie (60 x 30) / 100 = 18 litres.
Thus the total quantity of water in
100 litres of mixture is 8 + 18 = 26 litres or 26%
7.
Average
weight of 47 balls is 4 gm. If the weight of the bag is taken into account the
average weight per ball increases by 0.3 gm. What is the weight of the bag?
Answer: 14.1 gm
It
is a very simple question. The increase in the average weight of the ball is
due to the weight of the bag. Hence the
weight of the bag is 0.3 x 47 = 14.1 gm8.
8.
A
and B invest in a business in the ratio 3 : 2. If 4% of the profit earned goes
to charity, then A’s share of profit is Rs 282.00 What is the total profit
earned?
Answer: Rs 489.58
4%
of the profit is given for charity. So, remaining profit is 96%. A’s share on
this is 3 parts out of 5. A’ share is 96 x 3/5 = 57.6% This is equal to Rs
282.00
Hence, the total profit is (282 x 100)
/ 57.6 = Rs 489.58
9.
An
inlet pipe can fill a pool in 5 hours. An outlet pipe can drain a full pool in
6 hours. If both these pipes were opened simultaneously in an empty pool, the
water would be filled up to what level after 5 hours?
Answer: up to 1/6 of the pool level.
The
inlet pipe take 5 hours to fill. So in one hour it will fill 1/5 of the pool.
The
outlet pipe can drain in 6 hours. So, in one hour it can drain 1/6 of the pool.
When
both the pipes are opened, the pool gets filled in I hour: 1/5 – 1/6 = 1/30.
In five hours the pool will get filled
up to 1/30 x 5 = 5/30 or 1/6.
10. Two 27.2 kohm resistors are in series
combination. This series is in parallel with another resistor of 29.3 kohm.
What is the total resistance?
Answer: 19.0432 kohm
Two
27.2 kohm resistors are in series . The total resistance of this is
27.2
+ 27.2 = 54.4kohm. Let this be R1
Now
R1 (54.4 kohm) is in parallel with R2 (29.3 kohm)
Then,
the total resistance is (R1 * R2) / (R1 + R2)
(54.4 * 29.3) / (54.4 + 29.3) = 19.0432
Kohm
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