TCS Questions-4

TCS Questions – 4

1.    If P is 30% of Q

   Q is 20% of M

   M is 50% of N   then, what percentage is P/N?

Answer: 3%.  Keep N value as 100 and proceed to answer.

2.    The sum of the ages of mother, daughter and an infant is 74. The mother is 46 years more than the sum of the ages of the daughter and the infant. The infant’s age is 0.4 of the daughter’s age. What is the age of the daughter?

  

Answer:  10 years      Let the age of the daughter be x. Then we have an equation

(46 + x + 4x/10) + x + 4x/10 = 74.  Working out, you will get the value of x as 10.

3.    A can finish a work in 8 hours, B in 10 hours and C in 12 hours. A, B, C together start a work and after two hours of working A leaves the work and B and C completes the remaining work. In how much time B and C completed the remaining work?

Answer: 23/11 hours or 2 1/11 hours.

A in 1 hour can do 1/8 work. B in 1 hour can do 1/10 work and C in 1 hour can do 1/12 work.

All the three worked for 2 hours. So, the work completed in 2 hours is

2/8 + 2/10 + 2/12 = 37/60. Remaining work completed by B and C is

1 – 37/60 = 23/60    B and C in 1 hour can do 1/10 + 1/12 = 11/60.

Hence for completing the remaining work of 23/60 B and C will take

(23/60) / (11/60) ie 23/11 hours.

4.    There are exactly four Sundays and four Thursdays in a month consisting of 31 days. What is the first day of the month?

Answer: Monday   (simple logic)

5.    J, K, L, M and N collect stamps. They collected a total of 100 stamps. None of them collected less than 10 stamps. Two among the five members collected the same number of stamps.

a)    Three members collected the same number of stamps as K and M together.

b)    L collected 3 more than the cube of an integer.

c)    The number collected by J was the square of an integer.

d)    Total number collected by K was either a square or cube of an integer.

Based on the above information we have the following possibilities.

The square can be 1^2, 2^2, 3^2, 4^2, 5^2, 6^2

The cube can be 1^3, 2^3, 3^3,  Now we shall try to find the values.

J + l + N = K + M = 50 stamps.

L collection could be either (2^3 + 3) or (3^3 + 3)

J collection could at best be (4^2), (5^2) or (6^2)

K collection could be any of the squares from 4^2 onwards or any one of the cubes.

The information says that two members collected the same number of stamps.

Thus if K collected 36 stamps, M would have collected 14 stamps.

Also if J collected 25 stamps, then L would have collected 11 stamps and N 14 stamps. These values full fill all the conditions.

The number collected by J was 25. ( in the choice answers this value is not there)

The number collected by K was 36

The difference in collection between L and M

6.    How many times the number 4 is used between 11 and 100?

Answer: 19 times ( simple logic)

7.    A and B start travelling from X to Y. A starts at 12.00 noon at a speed of 63 m/hr.

B starts at 1.30 p.m. at a speed of 84 m/hr. At what time will B be 34 m ahead of A?

Answer: at 7.42 p.m.

The relative speed between A and B is 21m. A had a jump start of 1.30 hrs over B and was moving at a speed of 63 m/hr. In this period A would have covered 94.50 m.

The question requires B to be 34 m ahead of A. Thus B will have to cover a total distance of 94.50 + 34 = 128.50 m. At a relative speed of 21m B will take

128.50/21 = 6.12 hours. He starts at 1.30 p.m. Thus at 1.30 + 6.12 = 7.42 hours.

8.    In a school having 60% girls of which 35% are poor. If the students are selected at random, what is the probability of selecting a poor girl out of total strength?

Answer: 21% or 21/100

Let the total number of students be 100. 60% are Girls. So there are 60 Girls. Of these 60 35% are poor girls. So the number of poor girls 21. The probability of selecting a poor girl is 21/100.

9.    There are 5 men and 11 women. In how many ways a panel can be formed of 11 members where the number of men shall not exceed 3.

The panel can be formed with 11 women , with 10 women and one man, with 9 women and two men, or with 8 women and 3 men.

Hence the answer is 11P11 + (11C10 x 5C1) + (11C9 x 5C2) + (11C8 x 5C3)

10.   If Y – W – U – S – Q are coded as 25 – 23 – 21 – 19 – 17, then how is S – F – A – Y – T is coded?

Answer: 19 – 06 – 01 – 25 – 20 ( The respective position of the letters in the alphabet)

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