Wednesday 24 July 2013

Cognizant Technology Solutions - Logical Reasoning (1)

Cognizant Technology Solutions – Logical Reasoning (1)
1.     
Each question given has a problem and two statements numbered I and II giving some information. You have to decide whether the given information is sufficient to answer the problem.
Mark your answer as
(a)   If the data given in statement I alone is sufficient to answer the question
(b)   If the data given in statement II alone is sufficient to answer the problem
(c)    If both statements are required to answer the problem
(d)   If the data in both statements Are not sufficient to answer the problem

Area of the rectangle PQRS?
(I)                 PQ = RS = 10
(II)               PR = RS = 10.5
From Statement (I) we get the length of the rectangle.
From Statement (II) we get the length of the diagonal. Using both the statements we can find the length of the breadth and thus the area. Hence,

Ans: c

2.      A teacher has 120 chocolates with him and distributes the same among the students. If there were four students less, then each of the other students would have got one chocolate more. How many students were there?

Let the number of students be x. The we have an equation   120 / x-4  minus 120 / x  = 1
Solving, we will get x^2 – 4x – 480 = 0.  Thus we get ( x - 24 ) ( x + 20 ) = 0

This will give you value for x as 24 and (-) 20. The answer cannot be (-) and hence the number of students is 24.

Ans: 24

3.      In a certain code, the symbol for 0 (zero) is * and symbol for 1 is $. Numbers greater than 1 are to be written using only these two symbols (Binary). The value of the symbol 1 doubles every time it shifts one place to the left. 

How to represent 361/19?

361/19 = 19.  19 when written in Binary will give a value 10011. Using the code we have the answer as $**$$

Ans: $**$$

4.       In a certain code, the symbol for 0 (zero) is * and symbol for 1 is $. Numbers greater than 1 are to be written using only these two symbols (Binary). The value of the symbol 1 doubles every time it shifts one place to the left. 

How to represent 2 + 9 / 11 * 2 ?

2 + 9 / 11 * 2  =  40 / 11         40 in Binary  is  10100  using the code  $*$**

                                                11 in Binary is   1011    using the code  $*$$


Ans:   $*$** / $*$$
5.      In a certain code, the symbol for 0 (zero) is * and symbol for 1 is $. Numbers greater than 1 are to be written using only these two symbols (Binary). The value of the symbol 1 doubles every time it shifts one place to the left. 

How to represent L.C.M. of ( 3, 5, 11 ) + 13   ?
LCM of 3, 5, 11 is 165.   165 + 13 = 178.
178 in Binary is  10110010   using the code
 Ans:   $*$$**$*
6.      Two premises are given hereunder and four choice conclusions are provided. Identify the right conclusion.
(I)                 All students are not intelligent.
(II)               Only intelligent pass the examination.
Conclusion:
(a)    Some students are intelligent
(b)   Some students who pass the examination are intelligent
(c)    Some students pass the examination
(d)   None of the above

Ans:     (b)

7.      Two premises are given hereunder and four choice conclusions are provided. Identify the right conclusion.
(I)                 All boys are handsome
(II)               Some handsome are cheaters
Conclusion:
(a)   All handsome are boys
(b)   Some boys who are handsome are cheaters
(c)    Some cheaters who are handsome are boys
(d)   None of the above                                  Ans:      (d)
8.      Two premises are given hereunder and four choice conclusions are provided. Identify the right conclusion.

(I)                 Some teachers are adults
(II)               Some adults are poets
Conclusion:
(a)   Some teachers are poets
(b)   Some teachers who are adults are poets
(c)    Some adults who are not teachers are poets
(d)   None of the above

Ans:     (d)

9.      Two premises are given hereunder and four choice conclusions are provided. Identify the right conclusion.

(I)                 All P’s are a’s
(II)               All a’s are R’s
(III)             All R’s are S’s
(IV)             Some a’s are T’s
Conclusion:
(a)   Some P’s are T’s
(b)   Some P’s which are a’s and S’s are T’s
(c)    No P’s which are a’s are T’s
(d)   None of the above.

Ans:    (d)

10.   Given here is a statement. Which of the conclusions that logically follow the statement.

I will do my home-work if I have time.
Conclusions:
(a)   I have time
(b)   I will do my home-work
(c)    I will not do my home-work
(d)   I don’t have time

(i)                 (a) and (b)       (ii)        (c) and (d)       (iii)     (d) and (c)
(iv)       None of the above

Ans:     (iii)





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