HCL - Aptitude
1. How many of the integers between 25 and 45 are even?
(a) 21
(b)20 (c)11 (d)10
(e)9
Ans: (d)
2. If the taxi fares were Re 1.00 for the first 1/5 mile
and Rs 0.20 for each subsequent 1/5 miles thereafter, then what would be the
fare for a trip of 3 miles?
(a) Rs
1.56 (b)Rs
2.40 (c)RS 3.00 (d)Rs 3.80 (e)Rs 4.20
Ans: (d)
(The fare for the first mile
will be Rs 1.80 and for every subsequent mile it will be Re 1.00)
3. A computer routine was developed to generate two
numbers (x and y) the first being a random
number between 0 and 100 inclusive, and the second being
less than or equal to the square root
of the first. Each of the following pair satisfies the
routine except:
(a) (99,10)
(b)
(85,9) (c) (50,7) (d) (1,1) (e) (1,0)
Ans: (a)
( easy to answer from the
choice. Square of 10 will be 100 and will not meet the condition)
4. A warehouse had a square floor with area 10,000 sq.
meters. A rectangular addition was built
along one entire side of the warehouse that increased the
area of the floor by one-half as much as the original floor. How many meters
did the addition extend beyond the original buildings?
(a) 10
(b) 20 (c) 50 (d)
200 (e) 500
Ans: (c)
(The area of the square floor is 10,000 sq. meters. Hence each side
is 100 meters. After the rectangular addition the area has become 10000 + 5000
= 15,000 sq. meters. Hence the distance extended on one side is 100 + 50 = 150.
Area 100 * 150 = 15,000.)
Note: This question had
appeared in TCS 2014 paper also.
5. A digital wristwatch was set accurately at 8.30 a.m
and it started losing 2 seconds every 5 minutes.
What time was indicated on the watch at 6.30 p.m of the
same day if the watch had operated continuously during that time ?
(a) 5:56
(b) 5:58 (c) 6.00 (d) 6.23 (e) 6.26
Ans: (e)
(The watch will lose 24
seconds in one hour and in 10 hours will lose 240 seconds or 4 minutes)
6. A 5 litre jug contains 4 litres of a salt water
solution that is 15 percent salts. If 1.5 litres of the
solution spills out of the jug, and the jug is then
filled to capacity with water, approximately
what percent of the resulting solution in the jug is
salt?
(a) 7.5%
(b) 9.5% (c) 10.5% (d)
12% (e) 15%
Ans: (a)
The quantum of salt in the 4
ltr solution is 15% of 4 -> 0.6 ltr.
The salt spilled along with
1.5 ltr solution is 15% of 1.5 -> 0.225 ltr.
Remaining salt in the solution
is 0.6 – 0.225 -> 0.375 ltr.
Remaining solution 4 – 1.5 =
2.5 ltrs. Additional amount of water poured is 2.5 ltrs (Since the capacity of
the jar is 5 ltrs.
Quantum of salt in this is
0.375 ltrs and the percentage of salt is 0.375/5 * 100 = 7.50%.
7. A merchant sells an item at 20 percent
discount and still makes a gross profit of 20 percent on
the cost. What percent of gross profit on cost would it
have been if the item was sold without the discount?
(a) 20%
(b) 40% (c) 50% (d) 60% (e) 66.6%
Ans: (c)
Let the cost price be Rs
100.00 He makes a profit of 20% after allowing discount.
So, the realised price is Rs
120.00 and his profit is Rs 120 – Rs 100 = Rs 20 (20%)
This realised price is after
allowing a discount of 20%. In other words the realised price
Is 80% of the marked up price.
Hence the marked price is 120
* 100/80 = Rs 150.00
If the discount was not
allowed this would have been the selling price and the profit
Percentage on cost would be Rs
150 – Rs 100 = Rs 50 (50%)
8. A millionaire bought a job lot of hats of which 1/4 were
brown. The millionaire sold 2/3 of the
hats including 4/5 of the brown hats. What fraction of
the unsold hats was brown?
(a) 1/60
(b) 1/15 (c) 3/20 (d) 3/5 (e)
3/4
Ans: (c)
For convenience sake let us
assume the total number of hats purchased as 300.
Of this, the Brown hats were
1/4th equals to 75 hats.
2/3 of the total hats were
sold. ie 200 hats were sold including 4/5 of the brown hats ie 60 hats.
Remaining total hats were 300 –
200 = 100.
Remaining Brown hats were 75 –
60 = 15. Fraction of unsold Brown hats was 15/100 = 3/20.
Note: Similar question had
appeared in TCS 2014 papers.
9. How many integers n greater than and less than 100 are
there such that, if the digits of n are
reversed, the resulting integer is n+9 ?
(a) 5
(b) 6 (c) 7 (d) 8 (e) 9
Ans: (d)
Lets say, n=10x+y as 100>n>10 so , if we reverse the
digit , n becomes 10y+x but according to Qs, 10y+x = n-9 => 10y+x = 10x+y -
9 => 9(x-y) = 9 => x-y =1 hence we need to find out the 2 digits where
diff is 1 so, the Nos are , 21(12) , 32(23) , 43(34) , 54(45) , 65(56) ,
76(67), 87(78) , 98(89) There are only eight such numbers. Hence the answer is 8.
10.An investor purchased shares of a company at a certain
price. If the shares increase in price by Re 0.25 per share and the total
increase for the x shares was Rs 12.50, how many shares of the company he had
purchased?
(a) 25
(b) 50 (c) 75 (d) 100 (e) 125
Ans: (b)
11. At a special sale, 5 tickets can be purchased for the
price of 3 tickets. If 5 tickets are purchased
at the sale, the amount saved will be What percent of the
original price of the 5 tickets?
(a) 20% (b)
33.3% (c) 40% (d)
60% (e) 66.6%
Ans: (c)
Let cost of each ticket be Rs
20.00 Then cost of 5 tickets would be Rs 100.00
But, 5 tickets were purchased
for the cost of 3 tickets -> 20 x 3 = 60.00
Hence the amount saved is Rs
100.00 – Rs 60.00 -> Rs 40.00 or 40%
12. Working independently, Tina can do a certain job in
12 hours. Working independently, Ann can
do the same job in 9 hours. If Tina Works independently
at the job for 8 hours and then Ann
works independently, how many hours will it take Ann to
complete the remainder of the jobs?
(a) 2/3 (b)
3/4 (c)
1 (d) 2 (e) 3
Ans: (e)
Tina in one hour can do 1/12
job and 8 hours she has done 8/12 or 2/3 job.
Remaining job is 1 – 2/3 =
1/3.
Ann in one hour can do 1/9 job
and for completing the remaining 1/3 job she would have taken
(1/3)/(1/9) -> 3 hours.
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